Posted by **HELP ME PLEASEEEE** on Thursday, October 20, 2011 at 4:20pm.

The marching band, cheerleaders, and chaperones are traveling by bus to play in the Citrus Bowl parade in Orlando. There are 216 bank members, 32 cheerleaders, and 40 chaperones making the trip. They can rent any number of one type of bus shown in the charter below.

BUSES AVAILABLE FOR RENT

Number of Passangers 20 32 44

Cost per Day $200 $265 $400

What is the least amount they must spend for everyone to travel to the Citrus Bowl? You have four options:

f)$1,855; g)$2,385; h)$2,800; i)$3,000

Can you please give me the answer and explain the procedure. Thank you very much for your help.

- Math -
**Ms. Sue**, Thursday, October 20, 2011 at 4:31pm
First, divide the total number, 288, by the number of passengers each bus can carry. Remember that you can't rent a part of a bus.

Then multiply each cost by the number of buses needed.

I'll be glad to check your answer.

- Math -
**John Smith**, Thursday, October 20, 2011 at 4:37pm
Bus No 1 : 20 people for 200

for 298 people = 298/20 = 14.9 ~ 15

15 * 200 = $3000

Bus No 2 : 32 people for 265

for 298 people = 298/32 = 9.3 ~ 10

10 * 265 = $2650

Bus No 3 : 44 people for 400

for 298 people = 298/44 = 6.7 ~ 7

7 * 400 = $2800

It seems like that one of the option is missing which is 2650 and smallest amount of all mentioned. Hope this helps.

- Math -
**Ms. Sue**, Thursday, October 20, 2011 at 4:40pm
I didn't get the same answer as John Smith.

Only 288 people are traveling, not 298.

- Math -
**John Smith**, Thursday, October 20, 2011 at 4:42pm
Bus No 1 : 20 people for 200

for 288 people = 288/20 = 14.4 ~ 15

15 * 200 = $3000

Bus No 2 : 32 people for 265

for 288 people = 288/32 = 9

9 * 265 = $2385

Bus No 3 : 44 people for 400

for 288 people = 288/44 = 6.5 ~ 7

7 * 400 = $2800

Sorry got it wrong last time. but its ok now. Option g is correct answer

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