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February 1, 2015

February 1, 2015

Posted by **HELP ME PLEASEEEE** on Thursday, October 20, 2011 at 4:20pm.

BUSES AVAILABLE FOR RENT

Number of Passangers 20 32 44

Cost per Day $200 $265 $400

What is the least amount they must spend for everyone to travel to the Citrus Bowl? You have four options:

f)$1,855; g)$2,385; h)$2,800; i)$3,000

Can you please give me the answer and explain the procedure. Thank you very much for your help.

- Math -
**Ms. Sue**, Thursday, October 20, 2011 at 4:31pmFirst, divide the total number, 288, by the number of passengers each bus can carry. Remember that you can't rent a part of a bus.

Then multiply each cost by the number of buses needed.

I'll be glad to check your answer.

- Math -
**John Smith**, Thursday, October 20, 2011 at 4:37pmBus No 1 : 20 people for 200

for 298 people = 298/20 = 14.9 ~ 15

15 * 200 = $3000

Bus No 2 : 32 people for 265

for 298 people = 298/32 = 9.3 ~ 10

10 * 265 = $2650

Bus No 3 : 44 people for 400

for 298 people = 298/44 = 6.7 ~ 7

7 * 400 = $2800

It seems like that one of the option is missing which is 2650 and smallest amount of all mentioned. Hope this helps.

- Math -
**Ms. Sue**, Thursday, October 20, 2011 at 4:40pmI didn't get the same answer as John Smith.

Only 288 people are traveling, not 298.

- Math -
**John Smith**, Thursday, October 20, 2011 at 4:42pmBus No 1 : 20 people for 200

for 288 people = 288/20 = 14.4 ~ 15

15 * 200 = $3000

Bus No 2 : 32 people for 265

for 288 people = 288/32 = 9

9 * 265 = $2385

Bus No 3 : 44 people for 400

for 288 people = 288/44 = 6.5 ~ 7

7 * 400 = $2800

Sorry got it wrong last time. but its ok now. Option g is correct answer

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