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April 18, 2014

Homework Help: Chemistry

Posted by Kevin on Thursday, October 20, 2011 at 1:21pm.

so i had to calculate the pH of a 100ml solution of .10M acetic acid (ka=1.8x10(-5) I came out to 2.87. But then, they want the pH if 50ml HCL is added. So i thought...Ka = x2/.15M, therefore the square root of .15M x 1.8x10(-5) = .00164(concentration). So -log(.00164) = 2.78. Can you verify this, or tell me where i went wrong?

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