October 7, 2015

Homework Help: Chemistry

Posted by Kevin on Thursday, October 20, 2011 at 1:21pm.

so i had to calculate the pH of a 100ml solution of .10M acetic acid (ka=1.8x10(-5) I came out to 2.87. But then, they want the pH if 50ml HCL is added. So i thought...Ka = x2/.15M, therefore the square root of .15M x 1.8x10(-5) = .00164(concentration). So -log(.00164) = 2.78. Can you verify this, or tell me where i went wrong?

Answer this Question

First Name:
School Subject:

Related Questions

More Related Questions