Homework Help: chemistry

Posted by Rema on Thursday, October 20, 2011 at 12:29pm.

You were given 25.00 ml of an acetic acid solution of unknown concentration. You find that it requires 29.60 ml of a 0.1050 M NaOH solution to exaclty neutralize this sample.

A) What is the molarity of the acetic acid solution?

B) what is the percentage of acetic acid in the solution? Assume the density of the solution is 1 g/ml.

chemistry - DrBob222, Thursday, October 20, 2011 at 3:57pm
HAc + NaOH ==> NaAc + H2O so it is a 1:1 titration mixture. Therefore,
mLacid x M acid = mL base x M base.
Substitute and solve for the one unknown.
B) Determine moles acetic acid, then grams.
moles = M x L
grams = moles x molar mass
%acetic acid = (grams acetic acid/mass sample)*100 = ??

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