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November 29, 2014

November 29, 2014

Posted by **tracy** on Thursday, October 20, 2011 at 11:17am.

h = -16t^2 + 50t + 4

- algebra -
**Steve**, Thursday, October 20, 2011 at 11:48amOK. The four questions you posted are all basically the same. Here's help on this one:

The baseball will land when the height is zero.

So, you need to solve

-16t^2 + 50t + 4 = 0

Unless you see an abvikus factoring, use the quadratic formula:

for f(x) = ax^2 + bx + c,

x = (-b ± √(b^2 - 4ac)]/2

Here, a = -16

b = 50

c = 4

t = (-50 ± √(50^2 - 4(-16)(4))]/-32

= (-50 ± √(2500 + 256)]/-32

= (-50 ± √2756]/-32

= (-50 ± 52.5)]/-32

t = -0.07 or 3.2

Since time is positive, use t = 3.2 sec

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