Posted by **sal** on Wednesday, October 19, 2011 at 11:38pm.

A car leaves an intersection traveling east. Its position t sec later is given by

x = t2 + t

ft. At the same time, another car leaves the same intersection heading north, traveling

y = t2 + 3t ft

in t sec. Find the rate at which the distance between the two cars will be changing 3 sec later. (Round your answer to one decimal place.)

- calculus -
**Damon**, Thursday, October 20, 2011 at 4:49am
x = t^2 + 1t which is 10 at t=3

y = t^2 + 3t which is 18 at t=3

dx/dt = 2 t + 1 which is 7 at t=3

dy/dt = 2 t + 3 which is 9 at t=3

r^2 = x^2 + y^2 = 434 at t = 3

so at t = 3, r = 20.6

2 r dr/dt = 2 x dx/dt + 2 y dy/dt

20.6 dr/dt = 10(7) + 18(9)

dr/dt = 11.3 ft/s

- calculus -
**Methendis**, Tuesday, March 1, 2016 at 11:25pm
apple

- calculus -
**Methendis**, Tuesday, March 1, 2016 at 11:30pm
x would actually be 12 not 10

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