Question Part
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Submissions Used
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A block of mass m = 2.00 kg is released from rest at h = 0.400 m from the surface of a table, at the top of a θ = 35.0° incline as shown below. The frictionless incline is fixed on a table of height H = 2.00 m.
(a) Determine the acceleration of the block as it slides down the incline.
m/s2
(b) What is the velocity of the block as it leaves the incline?
m/s
(c) How far from the table will the block hit the floor?
Your response differs from the correct answer by more than 10%. Double check your calculations. m
(d) How much time has elapsed between when the block is released and when it hits the floor?
s
YOu probably would gain more if you stated what you did, and let us analyze that.
To solve this problem, we can use the principles of Newtonian mechanics and kinematics. Let's break down each part of the question and explain how to find the answers.
(a) Determine the acceleration of the block as it slides down the incline.
To find the acceleration, we need to consider the forces acting on the block. The only force in the horizontal direction is the component of the gravitational force parallel to the incline. This force can be calculated using the formula:
F = m * g * sin(θ),
where m is the mass of the block, g is the acceleration due to gravity, and θ is the angle of the incline.
Substituting the given values:
m = 2.00 kg,
g = 9.8 m/s^2,
θ = 35.0°,
we can calculate the acceleration:
a = F / m = (m * g * sin(θ)) / m = g * sin(θ).
Plugging in the values:
a = 9.8 m/s^2 * sin(35.0°).
Calculating this gives us the answer.