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Posted by on Wednesday, October 19, 2011 at 8:28pm.

To make a bounce pass, a player throws a 0.60-kg basketball toward the floor. The ball hits the floor with a speed of 5.5 m/s at an angle of 72° from the vertical. If the ball rebounds with the same speed and angle, what was the impulse delivered to it by the floor?


what equation do i use to set this up? i have been trying for an hour and keep getting it wrong

  • physics - , Sunday, October 30, 2011 at 9:31pm

    I had trouble at first with this, too. Okay, so the moment that the ball is actually touching the floor, its velocity is zero, right? Then its velocity goes back to 5.5. Ignore the angle thing--it isn't important here.

    Now use the Impulse equation I= change in momentum= m(final velocity-initial velocity).

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