Posted by **Cassie** on Wednesday, October 19, 2011 at 5:24pm.

Two Diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10m apart?

Please help, I am very confused with this question, I have completed all other but I am unsure about how to answer this. Any help is greatly appreciated!

- Physics -
**Henry**, Thursday, October 20, 2011 at 6:56pm
d1 = Vo*t + (g/2)t^2. Vo = 0.

d1 = (g/2)t^2.

d2 = (g/2)(t-1)^2.

d1 = d2 + 10.

(g/2)t^2 = (g/2)(t-1)^2 + 10,

4.9t^2 = 4.9(t-1)^2 + 10,

4.9t^2 - 4.9(t-1)^2 = 10,

divide both sides by 4.9:

t^2 - (t-1)^2 = 2.04,

t^2 - (t^2-2t+1) = 2.04,

t^2 - t^2 + 2t - 1 = 2.04,

2t - 1 = 2.04,

2t = 3.04,

t = 1.52s.

## Answer this Question

## Related Questions

- science - Two diamonds begin a free fall from rest from the same height, 1 s ...
- physics - Two diamonds begin a free fall from rest from the same height 0.9 s ...
- physics - Two diamonds begin a free fall from rest from the same height 0.9 s ...
- PLUS ONE - two bodies begin to fall freely from the same height the second t ...
- math - I'm working on a school math project, and i need to make my own 2 plans, ...
- science - i need some help on this question a diamond cutter has a raw diamond ...
- sorry again - I n]have to find four crystalline substances and i found diamonds...
- really need some help with this - i need some help on this question a diamond ...
- Physics - Two identical 19.8-kg spheres of radius 12 cm are 29.2 cm apart (...
- Physics - Two identical 21.2-kg spheres of radius 12 cm are 30.6 cm apart (...