Posted by **teresa** on Wednesday, October 19, 2011 at 8:57am.

8. A pitcher throws a baseball off a 20m high cliff into a canyon at 30degrees above the horizon at an initial velocity of 35m/s. How far will the ball travel horizontally from the pitcher? Assume no air resistance.

9. How high will the ball get from the bottom of a canyon?

10. How fast will the ball be moving when it hits the ground?

- physics -
**bobpursley**, Wednesday, October 19, 2011 at 9:20am
vertical velocity initial: 20sin30=10m/s

time in air:

hf=hi+10*t-4.9t^2

0=20+10t-4.9t^2 solve for t, time in air.

horizonal distance= 20cos30*t

how high? at the top, v is zero in the vertical, 0=10-9.8t solve for time to top, t hf=20+10t-4.9t^2 solve for hf

how fast?

use the time in air t,

vf=20t-9.8t^2

- physics -
**bobpursley**, Wednesday, October 19, 2011 at 9:20am
oops, on how fast

vf=20-9.8t

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