Posted by teresa on .
8. A pitcher throws a baseball off a 20m high cliff into a canyon at 30degrees above the horizon at an initial velocity of 35m/s. How far will the ball travel horizontally from the pitcher? Assume no air resistance.
9. How high will the ball get from the bottom of a canyon?
10. How fast will the ball be moving when it hits the ground?

physics 
bobpursley,
vertical velocity initial: 20sin30=10m/s
time in air:
hf=hi+10*t4.9t^2
0=20+10t4.9t^2 solve for t, time in air.
horizonal distance= 20cos30*t
how high? at the top, v is zero in the vertical, 0=109.8t solve for time to top, t hf=20+10t4.9t^2 solve for hf
how fast?
use the time in air t,
vf=20t9.8t^2 
physics 
bobpursley,
oops, on how fast
vf=209.8t