Wednesday

September 3, 2014

September 3, 2014

Posted by **Anonymous** on Wednesday, October 19, 2011 at 1:22am.

point P on a straight shoreline. Its light makes 3 revolutions

per minute. How fast is the beam of light moving along the shoreline

when it is 1.7 kilometers from

P

?

- Calculus -
**Steve**, Wednesday, October 19, 2011 at 11:49amDraw a diagram. If x is the distance from P, and θ is the angle swept out by the beam, measured from the line joining the lighthouse and P,

x/4 = tan θ

dx/4 = sec^2 θ dθ

dx = 4 sec^2 θ * 3 * 2π

So, what is sec θ? tan θ = 1.7/4 = 0.425

sec^2θ = 1+tan^2θ = 1.18

dx = 4*1.18*3*2π = 88.97 mi/min

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