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July 29, 2014

July 29, 2014

Posted by **Erica** on Wednesday, October 19, 2011 at 1:05am.

The integral of [ (sq. root (1 + ln x)) ((ln x)/x) dx]

Im confused on what i should substitute u and du for.

Thank you so much!!

- Calc -
**Steve**, Wednesday, October 19, 2011 at 11:37amLet u = 1+ln x

so,

du = 1/x dx

ln x = u-1

So, we have

u^1/2 * (u-1) du

= u^3/2 - u^1/2 du

Integrate that to get

2/5 u^5/2 - 2/3 u^3/2

=

2/5 (1 + ln x)^5/2 - 2/3 (1+ln x)^3/2

Check your work by taking the derivative. Trust me -- it comes out right.

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