A six kilogram object undergoes an acceleration of 2.0 meters per second squared. Part a. What is magnitude of the net force acting on the object? Part B. If the same force is applied to a 4 kilogram object what acceleration is produced?
physics - Steve, Wednesday, October 19, 2011 at 11:21am
Trot out the well-worn formula:
F = ma
F = 6*2 = 12
12 = 4a
3 = a