3n+40=-6(-2n+1)+1
3n+40=-6(-2n+1)+1
3n + 40 = 12n - 6 + 1
40 + 6 - 1 = 12n - 3n
45 = 9n
45/9 = n
? = n
5. And wouldn't it be -12n?
No. Multiplying 2 negatives produces a positive.
-6 * -2n = 12n
oh wait never mind. I see my mistake now. Thanks for the help.
You're welcome.
To solve the equation 3n + 40 = -6(-2n + 1) + 1, we will follow these steps:
Step 1: Distribute on the right side of the equation:
-6(-2n + 1) + 1 becomes 12n - 6 + 1.
Step 2: Combine like terms on both sides of the equation:
The equation now becomes 3n + 40 = 12n - 5.
Step 3: Isolate the variable terms on one side of the equation:
To isolate the variable terms, we can subtract 12n from both sides of the equation:
3n - 12n + 40 = 12n - 12n - 5.
-9n + 40 = -5.
Step 4: Isolate the constant term on one side of the equation:
To isolate the constant term, we can subtract 40 from both sides of the equation:
-9n + 40 - 40 = -5 - 40.
-9n = -45.
Step 5: Solve for the variable:
To solve for n, we can divide both sides of the equation by -9:
(-9n)/-9 = -45/-9.
n = 5.
Therefore, the solution to the equation 3n + 40 = -6(-2n + 1) + 1 is n = 5.