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July 30, 2014

July 30, 2014

Posted by **Erica** on Tuesday, October 18, 2011 at 9:02pm.

∫ sinx cos³x e^(1-sin²x) dx

I was going to substitute u= 1 - sin²x, but then i got du = ½ sinxcosx - ½ xdx, so im stuck.

Thank you so much!!

- Calc -
**MathMate**, Tuesday, October 18, 2011 at 9:59pmIsn't (1-sin²x)=cos²x?

You will end up with an expression containing cos(x) and ONE sin(x).

Try u=cos(x), du=d(cos(x))=-sin(x)dx

Do you see the light?

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