Wednesday

August 20, 2014

August 20, 2014

Posted by **Erica** on Tuesday, October 18, 2011 at 9:02pm.

∫ sinx cos³x e^(1-sin²x) dx

I was going to substitute u= 1 - sin²x, but then i got du = ½ sinxcosx - ½ xdx, so im stuck.

Thank you so much!!

- Calc -
**MathMate**, Tuesday, October 18, 2011 at 9:59pmIsn't (1-sin²x)=cos²x?

You will end up with an expression containing cos(x) and ONE sin(x).

Try u=cos(x), du=d(cos(x))=-sin(x)dx

Do you see the light?

**Related Questions**

Integration? - Sorry, i have a load of questions on integration... thanks for ...

Calculus AP - hi again im really need help TextBook: James Stewart:Essential ...

Calculus - First make a substitution and then use integration by parts to ...

Calculus - First make a substitution and then use integration by parts to ...

Math integrals - What is the indefinite integral of ∫ [sin (π/x)]/ x^...

Calculus - I have two questions, because I'm preparing for a math test on monday...

Calculus AP - Evaluate the integral interval from [0 to pi] t sin(3t)dt Use ...

Integral - That's the same as the integral of sin^2 x dx. Use integration by ...

Calculus AP - Use the table of integrals to find int cos^4 3x dx I found the ...

Calculus - Use either substitution or integration by parts to evaluate the ...