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First make an appropriate substitution and then use integration by parts to evaluate the indefinite integrals:

∫ sinx cos³x e^(1-sin²x) dx

I was going to substitute u= 1 - sin²x, but then i got du = ½ sinxcosx - ½ xdx, so im stuck.

Thank you so much!!

  • Calc - ,

    Isn't (1-sin²x)=cos²x?
    You will end up with an expression containing cos(x) and ONE sin(x).

    Try u=cos(x), du=d(cos(x))=-sin(x)dx

    Do you see the light?

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