A teacher is shot out of a cannon. He leaves the barrel at an angle of 25.0o to the ground with a velocity of 45.0 m/s. What is the teacher's horizontal velocity?

To find the teacher's horizontal velocity, we need to use trigonometry. The horizontal velocity component can be found by using the formula:

Horizontal velocity = velocity * cos(angle)

Here, the given velocity is 45.0 m/s and the angle is 25.0 degrees.

Plug these values into the formula and calculate the horizontal velocity:

Horizontal velocity = 45.0 m/s * cos(25.0 degrees)

To obtain the answer, evaluate the cosine of 25.0 degrees and multiply it by 45.0 m/s.

Using a calculator: cos(25.0) ≈ 0.9063

Horizontal velocity = 45.0 m/s * 0.9063

Horizontal velocity ≈ 40.7845 m/s

Therefore, the teacher's horizontal velocity is approximately 40.8 m/s.