An olympic diver springs forward off a 10 meter platform. He enters the water 8 meters beyond the edge of the platform. how much time does it spend in the air?
physics - drwls, Tuesday, October 18, 2011 at 9:51pm
The key is to assume that he takes off horizontally. Few Olympic divers do that. You are in the air less and can't do as many maneuvers.
The time to hit the waterl is in this case
t = sqrt(2H/g) = 1.429 seconds
Where he lands doesn't matter. That depends upon his horizontal takeoff velocity
physics - Anonymous, Wednesday, November 19, 2014 at 9:06pm