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a portion (10.0 ml)of a solution containing the chloride anion was treated with silver nitrate to yield a precipitate (0.1713 g) of the silver chloride. calculate the molar concentration of the chloride anion in the solution. first write the equation.

  • chemistry -

    Convert 0.1713 g AgCl to g Cl
    moles AgCl = 0.1713/molar mass AgCl
    moles Cl = moles Ag since there is 1 mole Cl in 1 mole AgCl.
    Then M = moles Cl/L soln.
    AgNO3 + Cl^ ==> AgCl + NO3^-

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