Posted by **Tiffany** on Tuesday, October 18, 2011 at 4:14pm.

Sally has three times as many dimes as nickels and twice as many quarters as dimes.In all she has $5.55. How many coins of each type does she have?

Let 2x=quarters

3x=dimes

x=nickles <---- is that correct please help put

- MATH (PLease HELp) -
**abby**, Tuesday, October 18, 2011 at 4:24pm
i think the answer is

3 nickels .15

9 dimes .90

18 quarters 4.50

total 5.50

- MATH (PLease HELp) -
**Steve**, Tuesday, October 18, 2011 at 4:32pm
It's easy enough to check.

The numbers add up, and the values add up.

You added wrong at the very end. 4.50 + .90 + .15 does indeed make 5.55

However, your equations do not represent the facts:

x = nickels

3x = dimes

2(3x) = 6x = quarters

5x + 10(3x) + 25(6x) = 555

185x = 555

x=3

- MATH (PLease HELp) -
**patricia**, Monday, January 2, 2012 at 6:43pm
Megan has three times as many quarters than nickels. She has one less dime than the number of quarters. If she has a total of $4.30, how many of each coin does she have ?

- MATH (PLease HELp) -
**Trevor**, Friday, March 2, 2012 at 11:36pm
Nickels = x

Quarters = 3x

Dimes = 3x-1

Plug in equation with coin values in ()...

(5)x + (25)3x + (10)3x-1 = 430

5x + 75x + 30x - 10 = 430

80x + 30x - 10 = 430

110x -10 = 430

110x -10 +10 = 430 + 10

110x = 440

x = 4

Nickels = 4 (x)

Quarters = 12 (3x)

Dimes = 11 (3x-1)

4x5=20 N

12x25=300 Q

11x10=110 D /

/

20+300+110= 430 cents \/

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