posted by mary on .
Have 250 mL of a 0.80 M solution of silver nitrate AgNO3 dissolved in water. how many grams of AgNO3 does the solution contain
250 mL of 0.8M solution means there are 0.2M of AgNO3
The mole weight of AgNO3 is
107.9 + 14.01 + 3*16.0 = 169.91g
You have .2M, or 33.99g