Posted by Anonymous on Tuesday, October 18, 2011 at 3:34pm.
Inequalities involving parabolas can get interesting.
Solve as an equation:
2t^2 - t -3 = 0
(t+1)(2t-3) = 0
t = -1 or 3/2
Think now of the graphs of 2t^2 - 3 and t
You want the region where the parabola is below the line. That is,
-1 <= x <= 3/2
Of course, you can do analysis of the factors, considering positive and negative values, but it's a lot more work, and gets you the same result.
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