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October 25, 2014

October 25, 2014

Posted by **Brianb** on Tuesday, October 18, 2011 at 9:10am.

- Physics -
**drwls**, Tuesday, October 18, 2011 at 9:19amConvert gallons/min to kg/second.

Then multiply the kg/s pumping rate by g*(height). That will equal the rate potential energy is added to the water, in watts.

You should do the calculation.

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