Tuesday

January 27, 2015

January 27, 2015

Posted by **Anonymous** on Monday, October 17, 2011 at 11:32pm.

- calculus -
**Reiny**, Monday, October 17, 2011 at 11:52pmFirst of all, both given points are on the curve, so

for

(0,2) ---> 2 = 0+0+0+d

so we know d=2

(-1,-2) ---> -2 = a(-1) + b(1) + c(1) + d

-a + b + c + 2 = -2

a - b - c = 4

y' = 3ax^2 + 2bx + c

since (0,2) is a max, we know y' = 0 when x = 0

0 = 3a(0) + 2b(0) + c

c = 0

y'' = 6ax + 2b

we know y'' = 0 when x = -1

0 = -6a + 2b

2b = 6a

b = 3a

so in a-b-c=4

a - 3a - 0 = 4

-2a = 4

a = -2 and b=-6 , c=0 , d=2

**then the function is**

y = -2x^3 - 6x^2 + 2

check my arithmetic.

**Answer this Question**

**Related Questions**

Calculus AB - Find a, b, c, and d such that the cubic function ax^3 + bx^2 + cx...

calculus - I needed help with these FRQ in my APCalc course. Any help or ...

Calculus - Let f(x) be a polynomial function such that f(-2)=5, f’(-2)=0 and f...

Calculus - Let f(x) be a polynomial function such that f(-2)=5, f'(-2)=0, and f...

Calculus - Let f(x) be a polynomial function such that f(4)=-1, f’(4)=2 and f”(4...

calculus - suppose f(x) is a function such that f(3)=5, f'(3)=0, and f''(3)=3. ...

calculus - determine the cubic function with 1 point of inflection and no ...

Calc - Let f be the function given by f(x)=2ln(x^2+3)-x with domain -3 is less ...

Pre-calculus - Find the critical point of the function y=-2(x-1)^2-3. Then, ...

Pre-calculus - Find the critical point of the function y=-2(x-1)^2-3. Then, ...