In a 1.0x10^-6 M soltution of HNO3(aq), identify the relative molar amounts of these species.

H2O , HNO3, H3O+,NO3-, OH-

I don't know what you mean by "relative" molar amounts.

If relative means "about", then
HNO3 = 0
(H3O^+) = about 1E-6 (technically it's slightly more than that because water contributes a little).
(OH^-) = about 1E-14/1E-6 (technically its a little less than this because the H^+ is slightly >1E-6
NO3^- = 1E-6M
(H2O) = about 55.5M

thank you!

To identify the relative molar amounts of these species in a 1.0x10^-6 M solution of HNO3(aq), you would need to consider the dissociation of HNO3 in water.

HNO3(aq) dissociates into H+ ions (H3O+) and NO3- ions in water. The water (H2O) molecules themselves do not dissociate.

First, let's consider the dissociation of HNO3:

HNO3(aq) → H+(aq) + NO3-(aq)

Since 1 molecule of HNO3 produces 1 H+ ion and 1 NO3- ion, in a 1.0x10^-6 M solution of HNO3(aq), the molar amount of H3O+ ions (or H+) would be equal to the molar amount of HNO3. Therefore, the relative molar amount of H3O+ is 1.0x10^-6 M.

The molar amount of NO3- ions would also be equal to the molar amount of HNO3 since they are produced in a 1:1 ratio. Thus, the relative molar amount of NO3- is also 1.0x10^-6 M.

As for OH- ions, they are not directly produced from the dissociation of HNO3. However, in a neutral solution, the concentration of OH- ions is equal to the concentration of H3O+ ions. Therefore, in this case, the relative molar amount of OH- ions is also 1.0x10^-6 M.

Finally, the relative molar amount of water (H2O) remains unchanged since it does not dissociate.