Posted by Melissa on Monday, October 17, 2011 at 10:31pm.
p(x) = -5x^2 + 400x - 2550
p'(x) = -10x + 400
= 0 for a max of p(x)
10x = 400
x = 40 -----> answer for b)
p(40) = -5(40^2) + 400(40) - 2550 = 5450 -- > a)
for c)
solve
4000 = -5x^2 + 400x - 2550
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