Posted by Sherry on .
write an equation of the line containing the specified point and perpendicular to the indicated line?
x -2 -2y= 3
x -5 = 2y
y = x/2 -5/2 The slope is 1/2, so the perpendicular slope to it would be -2.
For me, I find it easier to draw a graph. Find point (-2, -5) and draw a line with slope of -2. Once you hit the y-axis, the number on the axis is you're y-intercept. So the equation should be y = -2x -6
y = .5x -2.5 or y= 1/2x -5/2
So the slope of your line is -2
y+5=-2(x+2) y= -2x-4-5 y=-2x-9
And the winner is . . . the one which contains the given point.
-2(-2) - 6 = 4-6 = -2 Bzzt!
-2(-2) - 9 = 4 - 9 = -5 Ding Ding!