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November 28, 2014

Posted by **PLEASE HELP** on Monday, October 17, 2011 at 6:45pm.

- MATH Middle School -
**Reiny**, Monday, October 17, 2011 at 6:55pmfirst:

length --- x

width ----y

2nd:

length --- x+12

width --- y-5

xy + (x+12)(y-5) = 360

xy + xy + 12y - 5x - 60 = 360

2xy + 12y - 5x = 420

difference in perimeter = 2x + 2y - 2(x+12) - 2(y-5)

= 2x + 2y -2x - 24 - 2y +10

= -14

The fact that their areas total 360 cm^2 appears to not even enter the picture.

- Frank N. Osborne Middle School -
**Tyler**, Saturday, August 25, 2012 at 6:07pm14 cm

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