Posted by Katrina on Monday, October 17, 2011 at 4:38pm.
If a rock is thrown upward on the planet Mars with a velocity of 17 m/s, its height (in meters) after t seconds is given by H = 17t − 1.86t^2.
(a) Find the velocity of the rock after one second.
(b) Find the velocity of the rock when t = a.
(c) When will the rock hit the surface? (Round your answer to one decimal place.)
(d) With what velocity will the rock hit the surface?

Calc  Steve, Monday, October 17, 2011 at 4:58pm
As on earth, v = Vo  at where a = 1.86*2 on Mars.
So, v = 17  3.72t
v(1) = 173.72 = 13.28m/s
v(a) = 17  3.72a
Since h = t(171.86t)
h=0 when t = 0 (rock thrown)
and t = 9.14 (rock hits again)
The rock will hit the surface with the same speed it had when it left: 17m/s. However, as a velocity, it's falling, so v = 17m/s
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