Posted by PHY on .
a car traveling at a constant velocity of 30 m/sec passes an intersection at time t=0 45 seconds later a second car passes the same intersection and its traveling in the same direction at a constant velocity of 55 m/sec.
when does the second car overtake the first car?
how far have the cars traveled when this happens?

PHYSICS 
Henry,
When car #2 catches up, their distance from starting point will be equal:
1. d1 = d2,
30t = 55(t0.45),
30t = 55t  24.75,
55t  30t = 24.75,
25t = 24.75,
t = 0.99s.
2. d = V*t = 30 * 0.99 = 29.7m.