Posted by Brianna on Sunday, October 16, 2011 at 11:01pm.
You know that the denominator has to be zero at x=5 and x=-7
The hole means that the numerator and denominator are both zero at x=2
so, we can start with
f(x) = (x-2)/[(x-2)(x-5)(x+7)]
Now, we need a horizontal asymptote at y=14. That means that the numerator and denominator must have the same degree, x^n, with the highest degree having a coefficient in the numerator 14 times that in the denominator. So, the simplest one I can think of is
f(x) = 14x^2(x-2)/[(x-2)(x-5)(x+7)]
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