Thursday
April 17, 2014

Homework Help: Chemistry

Posted by Anonymous on Sunday, October 16, 2011 at 10:06pm.

A 0.4584 g sample of impure zinc chloride, ZnCl2, FW = 136.3 g/mole, was dissolved in water and excess silver nitrate was added to the solution. The mass of the dry silver chloride, AgCl, FW = 143.3 g/mole, produced was 0.8564 g. The balanced precipitation is: ZnCl2 (aq) + 2 AgNO3 (aq) --> 2 Agcl (s) + Zn(NO3)2 (aq).

1. Calculate the moles of zinc chloride present in the sample.

2. Calculate the mass of zinc chloride in the sample.

3. Calculate the percent purity of the zinc cholride in the sample.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

chemistry - Zinc reacts with hydrochloric acid according to the following ...
Chem - What is the ratio of atoms of CL over atoms of Zn? and what is the ...
chemistry - treatment of a 0.3203g sample of impure soduim chloride with an ...
chemistry - treatment of a 0.3203g sample of impure soduim chloride with an ...
chemistry - treatment of a 0.3203g sample of impure soduim chloride with an ...
Chemistry - An excess of zinc is added to 125 mL of 0.100 M HCl solution, What ...
chemistry - how many mililiters of a 0.27 M HCl solution are needed to react ...
chemistry - Zinc chloride (ZnCl2) is 52.02% chlorine by mass. What mass of ...
Chemistry - If a copper sample containing some zinc impurity is to be purified ...
chemistry - What is the mass of 4.54 10-2 moles of zinc chloride (ZnCl2)?

Search
Members