Posted by **Wooah** on Sunday, October 16, 2011 at 9:03pm.

A large painting in the style of Rubens is 3 feet longer than it is wide. If the wooden frame is 18 in wide and the area of the picture frame is 286 ft^2, find the dimensions of the painting.

I have the basic idea down of what I'm supposed to do to solve it.. But I just can't put it all together in my head. Helpppp

- Pre-Calc -
**Steve**, Monday, October 17, 2011 at 12:55pm
Always draw a diagram, then use what info you have been given.

width = w

length = w+3

Since the frame is 1.5' wide, the total width and length get increased by 3 ft for the entire framed picture.

picture area: width*length = w(w+3)

total framed area: (width+3)(length+3) = (w+3)(w+6)

The total area less the area of the picture is the area of the frame:

(w+3)(w+6) - w(w+3) = 286

w^2 + 9w + 18 - w^2 - 3w = 286

6w + 18 = 286

6w = 268

w = 44' 8"

wow! Big painting!

## Answer This Question

## Related Questions

- PRE-CALC - A large painting in the style of Rubens is 3 feet longer than it is ...
- Algebra - A rectangular picture is 4 inches longer than it is wide. The picture ...
- LW Magnate School Aba. Nigeria - The wooden frame of a picture is 20cm long and ...
- Math 8th Grade (Ms. Sue) ? - An artist makes a painting that is 12 feet by 9 ...
- Math - Hello there! Could You please help me with this Geometry word problem? ...
- Math - Hello there! Could You please help me with this Geometry word problem? ...
- painting - An artist makes a painting that is 12 feet by 9 feet. He paints a ...
- algebra - A rectangular picture is 2 inches longer than it is wide. When a frame...
- math - hw help - A rectangular picture is 3cm longer than its width, (x+3). A ...
- Algebra 2 - If a 20 in. by 30 in. picture has a wooden frame "x" in. wide ...

More Related Questions