Posted by Wooah on Sunday, October 16, 2011 at 9:03pm.
A large painting in the style of Rubens is 3 feet longer than it is wide. If the wooden frame is 18 in wide and the area of the picture frame is 286 ft^2, find the dimensions of the painting.
I have the basic idea down of what I'm supposed to do to solve it.. But I just can't put it all together in my head. Helpppp

PreCalc  Steve, Monday, October 17, 2011 at 12:55pm
Always draw a diagram, then use what info you have been given.
width = w
length = w+3
Since the frame is 1.5' wide, the total width and length get increased by 3 ft for the entire framed picture.
picture area: width*length = w(w+3)
total framed area: (width+3)(length+3) = (w+3)(w+6)
The total area less the area of the picture is the area of the frame:
(w+3)(w+6)  w(w+3) = 286
w^2 + 9w + 18  w^2  3w = 286
6w + 18 = 286
6w = 268
w = 44' 8"
wow! Big painting!
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