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October 20, 2014

October 20, 2014

Posted by **rachel** on Sunday, October 16, 2011 at 7:57pm.

- calculus -
**Reiny**, Sunday, October 16, 2011 at 8:45pmMake a diagram, and label the radius of the water level r, and the height of the water h

V = (1/3)πr^2h

but by ratios, r/h = 2/6 = 1/3

then r= h/3

V = (1/3)π(h^2/9)(h) = (π/27)h^3

dV/dt = (π/9)h^2 dh/dt

= (π/9)(3^2) (1) = π cubic inches/sec

check my arithmetic

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