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Find the volume of 0.120 M hydrochloric acid necessary to react completely with 1.51 g Al(OH)^3

  • chemistry - ,

    3HCl + Al(OH)3 ==> 3H2O + AlCl3

    moles Al(OH)3 = grams/molar mass
    Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles HCl.
    Then M HCl = moles HCl/L HCl. You know M and moles HCl, solve for L.

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