ANTACID TABLET OF WEIGHT 1.3183G WAS DISSOLVED IN 75 MLOF CONC. HCl OF 0.1807M IS TITRATED WITH 20.36ML OF CONC. NaOH OF 0.1481M . FIND MILIMOLES OF HCl ADDED, FIND MILIMOLES OF NaOH USED IN TITRATION, FIND MILIMOLES OF HCl THAT DID NOT REACT WITH ANTACID, FIND MILIMOLES OF HCl NEUTRALIZED BY TABLET, FIND MILIMOLES OF H+ NEUTRALIZED PER GRAM OF ANTACID FIND MILIMOLES OF H+ / G OF ANTACID TABLET.

I simply can't read a post in all caps that is this detailed.

To find the various values requested, we can follow these steps:

Step 1: Calculate the millimoles of HCl added:
Given that the concentration of HCl is 0.1807 M and the volume used is 75 mL, we can use the formula:
Millimoles of HCl added = Concentration (M) × Volume (L) × 1000
= 0.1807 × (75/1000) × 1000
= 13.5525 mmol

Step 2: Calculate the millimoles of NaOH used in titration:
Given that the concentration of NaOH is 0.1481 M and the volume used is 20.36 mL, we can use the formula:
Millimoles of NaOH used = Concentration (M) × Volume (L) × 1000
= 0.1481 × (20.36/1000) × 1000
= 3.029 mmol

Step 3: Calculate the millimoles of HCl that did not react with the antacid:
Subtract the millimoles of NaOH used (from Step 2) from the millimoles of HCl added (from Step 1):
Millimoles of HCl not reacted = Millimoles of HCl added - Millimoles of NaOH used
= 13.5525 mmol - 3.029 mmol
= 10.5235 mmol

Step 4: Calculate the millimoles of HCl neutralized by the tablet:
Given that 1 mole of HCl reacts with 1 mole of NaOH, the millimoles of HCl neutralized by the tablet is equal to the millimoles of NaOH used:
Millimoles of HCl neutralized = Millimoles of NaOH used
= 3.029 mmol

Step 5: Calculate the millimoles of H+ neutralized per gram of antacid:
Given that 1 mole of HCl reacts with 1 mole of NaOH, and the tablet is 1.3183 g, we can use the formula:
Millimoles of H+ neutralized per gram of antacid = Millimoles of HCl neutralized / Weight of antacid (g)
= 3.029 mmol / 1.3183 g
= 2.3008 mmol/g

Step 6: Calculate the millimoles of H+ per gram of antacid tablet:
To find the millimoles of H+ per gram of antacid tablet, we need to consider that the tablet is made up of HCl and antacid, and the antacid reacts with HCl. We have already determined the millimoles of HCl neutralized by the tablet (from Step 4). Therefore, we can use the formula:
Millimoles of H+ / g of antacid tablet = Millimoles of HCl neutralized / (Weight of antacid + Weight of HCl in tablet) (g)
= 3.029 mmol / (1.3183 g + Weight of HCl in tablet (g))

It is important to note that we need the weight of HCl in the tablet to complete this calculation. If the weight of HCl in the tablet is provided, you can substitute it into the formula to find the millimoles of H+ per gram of antacid tablet.

To find the answers to these questions, we need to use some basic stoichiometry and titration calculations. Let's go step by step:

1. Finding millimoles of HCl added:
- First, we need to calculate the number of moles of HCl added.
- The concentration of HCl is given as 0.1807 M, and the volume used is 75 mL (0.075 L).
- To find the moles, we multiply the concentration by volume:
Moles of HCl added = 0.1807 M * 0.075 L = 0.0135525 moles (or 13.5525 millimoles)

2. Finding millimoles of NaOH used in titration:
- Similar to the previous step, we multiply the concentration of NaOH by the volume used:
Moles of NaOH used = 0.1481 M * 0.02036 L = 0.003014216 moles (or 3.014216 millimoles)

3. Finding millimoles of HCl that did not react with antacid:
- The number of millimoles of HCl that did not react with the antacid will be the difference between the millimoles of HCl added and the millimoles of NaOH used:
Millimoles of HCl not reacted = Millimoles of HCl added - Millimoles of NaOH used
= 13.5525 - 3.014216
= 10.538284 millimoles

4. Finding millimoles of HCl neutralized by the tablet:
- Since an antacid is used to neutralize excess stomach acid (HCl), the number of millimoles of HCl neutralized by the tablet will be the millimoles of NaOH used in the titration.
- Thus, millimoles of HCl neutralized = Millimoles of NaOH used = 3.014216 millimoles

5. Finding millimoles of H+ neutralized per gram of antacid:
- To find the millimoles of H+ neutralized by the antacid per gram, we need to know the weight of the antacid tablet. The weight is given as 1.3183 grams.
- Let's assume the antacid tablet contained only one active ingredient that reacted with HCl.
- Then, the millimoles of H+ neutralized per gram of antacid can be calculated using the formula:
Millimoles of H+ neutralized per gram = (Millimoles of HCl neutralized) / (Weight of antacid tablet in grams)
= 3.014216 / 1.3183
≈ 2.286 millimoles/gram

6. Finding millimoles of H+ per gram of antacid tablet:
- Since the molecular weight of H+ is 1 g/mol, we can consider it as 1 millimole per milligram.
- Therefore, the millimoles of H+ per gram of antacid tablet will be the same as the millimoles of H+ neutralized per gram, calculated in the previous step.
- Thus, the millimoles of H+ per gram of antacid tablet ≈ 2.286 millimoles/gram.

I hope this explanation helps you understand how to solve these calculations!