Posted by anonymous on .
A small fish is dropped by a pelican that is rising steadily at 0.61 m/s.The acceleration of gravity is 9.81 m/s2.
How far below the pelican is the fish after the
3.1 s?

physics 
bobpursley,
Vi=.61
hfhi=Vi*t1/2 g t^2 you are looking for the (hfhi) where g=9.81, t=3.1