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March 26, 2017

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A small fish is dropped by a pelican that is rising steadily at 0.61 m/s.The acceleration of gravity is 9.81 m/s2.

How far below the pelican is the fish after the
3.1 s?

  • physics - ,

    Vi=.61

    hf-hi=Vi*t-1/2 g t^2 you are looking for the -(hf-hi) where g=9.81, t=3.1

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