Wednesday
April 16, 2014

Homework Help: Genetics

Posted by Billy on Saturday, October 15, 2011 at 9:53pm.

Suppose that a mating between phenotypically normal parents produces two normal daughter and one son affected with hemophilia (x-linked disorder).

1)What is the probability that both of the daughters are heterozygous carriers?

so obviously the two parents had to be carriers on the disorder for the son to have hemophilia..or is that different with x-linked?..anyway i decided to do 2/3 x 2/3 = 4/9 but the actual answer is 1/2 x 1/2 x 1/2= 1/8...i dont get where all the 1/2s come from.

2)If one of the daughters and a normal male produce a son, what is the probability that the son will be affected.
for this one i thought the answer was o but i think that the situation changes for x-linked the answer is 1/2 x 1/2= 1/4 but im still not seeing where the one halves come in..

please explain i really appreciate it!!

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