AT A CERTAIN TEMPERATURE, THE REACTION
CO(g) + 2H2(g) <----> CH3OH (g)
has Kc = 0.500
CO= 0.180 M
H2= 0.220 M
WHAT IS THE CONCENTRATION OF CH3OH?
i don't know if your are right but the answer that they give is 4.36x10'-3
It helps to read if you don't put everything in caps.
..........CO + 2H2 ==> CH3OH
initial..0.180.0.220.....0
change.....-x....-2x......x
equil...0.180-x..0.220-2x..x
Substitute into Kc expression and solve for x.
0.00436 is close but not quite correct. To prove that substitute back into the Kc expression and see if you get 0.5. You don't. I think you obtain 0.55.
I solved the cubic equation and obtained 0.003959 (which of course is too many significant figures) but if you substitute that into Kc you get exactly 0.500. I would round the answer to 0.00396M and that produces a Kc of 0.500 also.
To find the concentration of CH3OH, we can use the equilibrium expression and the given concentrations of CO and H2.
The equilibrium expression for the reaction is:
Kc = [CH3OH] / ([CO] * [H2]^2)
Given:
- Kc = 0.500
- [CO] = 0.180 M
- [H2] = 0.220 M
Let's substitute the given values into the equilibrium expression and solve for [CH3OH]:
0.500 = [CH3OH] / (0.180 * (0.220)^2)
To find [CH3OH], we can cross multiply and solve the equation:
[CH3OH] = 0.500 * (0.180 * (0.220)^2)
Now, let's calculate the value:
[CH3OH] = 0.500 * (0.180 * 0.0484)
[CH3OH] ≈ 0.0042 M
Therefore, the concentration of CH3OH is approximately 0.0042 M.