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A small fish is dropped by a pelican that is rising steadily at 0.61 m/s.The acceleration of gravity is 9.81 m/s2.

How far below the pelican is the fish after the
3.1 s?

  • physics -

    Just use your good old equation of motion

    s = Vot + 1/2 at^2

    s = .61t - 4.9t^2

  • physics -

    Of course, that's how far the fish drops. You have to add the height the bird has gained in the 3.1s.

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