Posted by Ian on Saturday, October 15, 2011 at 8:37pm.
your expression factors to
[(-8)^2(x+3)(2x+5)(x-1)]/[(x+4)^2(2x+5)(x+1)(x-1)]
So the graph is discontinuous at
x = -4, -5/2, -1, 1
There will be asymptotes at
x=-4 and x=-1
and holes at x= -5/2 and x=1
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