Monday

November 24, 2014

November 24, 2014

Posted by **Ian** on Saturday, October 15, 2011 at 8:37pm.

f(x)= [(x-8)^2(x+3)(2x^2+3x-5)]/[(x+4)^2(2x+5)(x-3)(x^2-1)]

- calculus -
**Reiny**, Saturday, October 15, 2011 at 9:59pmyour expression factors to

[(-8)^2(x+3)(2x+5)(x-1)]/[(x+4)^2(2x+5)(x+1)(x-1)]

So the graph is discontinuous at

x = -4, -5/2, -1, 1

There will be asymptotes at

x=-4 and x=-1

and holes at x= -5/2 and x=1

**Answer this Question**

**Related Questions**

calculus - Find the discontinuities of the given function. Classify them as a ...

AP Calculus - Consider the function f(x)= abs(x)(x-3)/9-x^2 a) what is the ...

Calculus (Discontinuities) - Suppose, f(x) = { (x - 1)^2 / x + 1 if x < 2 (x^...

limitas, asymptotes and discontinuities?? - f(x) = 1/(x^2-x-2) does f(x) have ...

calculus - Can anyone please explain to me that how can I find the ...

calculus - Locate the discontinuities of the function. y = 2/(1 + e^(1\/x))

calculus - find all discontinuities (16x/2x3-8x3=0)

asymptotes and discontinuity 2??? - consider the function f(x) = 1/x - 1 for x ...

Calculus - Suppose f(x) = [sin(x^2 - 4)]^ -1. Identify any points of ...

Calculus - Suppose f(x) = [sin(x^2 - 4)]^ -1. Identify any points of ...