Tuesday

September 30, 2014

September 30, 2014

Posted by **Kelsey** on Saturday, October 15, 2011 at 8:35pm.

- calculus -
**Reiny**, Saturday, October 15, 2011 at 9:53pmAt a given time of t minutes,

let the width of the water level be x ft

let the height of the water level be h ft

but by ratios, x/h = 3/3

x = h

V = area of triangle x 12

= (1/2)xh(12

= 6xh

= 6h^2

given : dV/dt = 2.5 ft^3/min

find dh/dt when h = 1

dV/dt = 12h dh/dt

2.5 = 12(1) dh/dt

dh/dt = 2.5/12 = 5/24 ft/min or appr. .208 ft/min

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