Posted by **justme** on Saturday, October 15, 2011 at 7:41pm.

Square OPQR has vertices O(0; 0), P(0; 8), Q(8; 8), and R(8; 0). The parabola

with equation y = a(x �� 2)(x �� 6) intersects the sides of the square OPQR at

points K, L, M, and N. Determine all the values of a for which the area of the

trapezoid KLMN is 36.

- math -
**Reiny**, Saturday, October 15, 2011 at 9:48pm
I made a sketch and found the following coordinates

K(0,12a) , L(2,0) , M(6,0) and N(8,12a

so the area of the trapezoid

= (KN + LM)(OK)/2 = 36

(8 + 4)(12a)/2 = 36

144a = 72

a = 72/144 = 1/2

## Answer this Question

## Related Questions

- math - pls. help.. The functions f and g satisfy f(x) + g(x) = 3x + 5 f(x) &#...
- Calc 2 - Use Taylor’s Estimate to bound the error of the n-th order Maclaurin ...
- calculus - Let h(x) = ( x2 + 2 if x > 2 ��mx if x 2 (a) Find ...
- calculus - Let f (x) = x3 ��3x2 +5x+2. Find the open intervals on ...
- circles - OPQR is a rhombus , three of whose vertices lie on a circle with ...
- cal - A ball is thrown directly upward from ground level with an initial ...
- math - The earth has a radius of 6,380 km. The formula for the volume of a ...
- physics - The electron in the Figure is travelling with a speed of 3 106 m/s...
- Math - Help, I am stuck: Find (A �� B) �� C, given A...
- physics - the region 0 < r < r1 is a charged insulating sphere with ...

More Related Questions