Posted by Bina on Saturday, October 15, 2011 at 7:36pm.
5 consecutive odd integers:
x, x+2, x+4, x+6, x+8
sum of 1st and 5th < 3 times the fourth by 1
x + (x+8) +1 = 3(x+6)
2x + 9 = 3x + 18
-x = 9
x = -9
so the numbers are
-9, -7, -5, -3, -1
check:
sum of 1st and 5th = -9 + (-1) = -10
3 times the 4th = 3(-3) = -9
sure enough: -10 is one less than -9
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