Posted by **Eric** on Saturday, October 15, 2011 at 5:41pm.

Consider the function y=x/(x+1)

a) Find dy/dx

b) Find the equation of the line tangent to the curve at x=-2

c) Find the equation of the line normal to the curve at x=1

- calculus -
**Damon**, Saturday, October 15, 2011 at 6:00pm
dy/dx = [(x+1)1 -x(1) ] / (x+1)^2

= 1/(x+1)^2

at x = -2

y = -2/-1 = 2 so through point (-2,2)

dy/dx = m = 1/1 = 1

so

y = 1 x + b

2 = -2 + b

b = 4

y = x +

for part c

find a new m at x = 1, y = 1/2

the m we want = -1/m

then repeat method of part b

## Answer This Question

## Related Questions

- Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...
- calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...
- calculus - Consider the curve given by the equation y^3+3x^2y+13=0 a.find dy/dx...
- Calculus - If F(x)=x^3−7x+5, use the limit definition of the derivative to...
- AP AB Calculus - Linear approximation: Consider the curve defined by -8x^2 + 5xy...
- calculus - Consider the function below. g(x) = 2 - x^3 (a) Find g'(0). (b) Use ...
- maths - given the equation of the curve as y=8-2x^2 (a) find equations of ...
- Calculus - Consider the curve given by y^2 = 2+xy (a) show that dy/dx= y/(2y-x...
- Calculus - Consider the curve -8x^2+5xy+y^3=-149 1. Find Dy/dx 2. write an ...
- Calc. - sketch the curve using the parametric equation to plot the points. use ...

More Related Questions