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March 29, 2015

March 29, 2015

Posted by **Eric** on Saturday, October 15, 2011 at 5:41pm.

a) Find dy/dx

b) Find the equation of the line tangent to the curve at x=-2

c) Find the equation of the line normal to the curve at x=1

- calculus -
**Damon**, Saturday, October 15, 2011 at 6:00pmdy/dx = [(x+1)1 -x(1) ] / (x+1)^2

= 1/(x+1)^2

at x = -2

y = -2/-1 = 2 so through point (-2,2)

dy/dx = m = 1/1 = 1

so

y = 1 x + b

2 = -2 + b

b = 4

y = x +

for part c

find a new m at x = 1, y = 1/2

the m we want = -1/m

then repeat method of part b

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