Posted by **Stephanie** on Saturday, October 15, 2011 at 12:55pm.

When you push a 1.70 kg book resting on a tabletop it takes 2.60 N to start the book sliding. Once it is sliding, however, it takes only 1.50 N to keep the book moving with constant speed. What are the coefficients of static and kinetic friction between the book and the tabletop?

- physics -
**Henry**, Sunday, October 16, 2011 at 6:16pm
Wb = mg = 1.7kg * 9.8N/kg = 16.66N.

Fb = (16.66N,0deg) = Force of book..

Fp = 16.66sin(0) = 0 = Force parallel to table.

Fv = 16.66cos(0) = 16.66N. = Force perpendicular to table.

1. Fap - Ff = 0, Fap = Force applied.

2.60 - Ff = 0, Ff = Force of friction.

Ff = 2.60,

u*Fv = 2.60,

16.66u = 2.60,

u = 0.156. = Static coefficient of friction.

2. 1.5 - Ff = 0,

Ff = 1.5,

u*Fv = 1.50,

16.66u = 1.5,

u = 0.09 = Kinetic coefficient of friction.

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