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October 24, 2014

October 24, 2014

Posted by **riley** on Saturday, October 15, 2011 at 12:20am.

- physics -
**drwls**, Saturday, October 15, 2011 at 1:49amIf they decelerate at the same rate, and skater 1 goes twice as far, she also glides for a period that is twice as long. She must have started with twice the velocity of the other skater. V1 = 2 V2

Skater 1 and skater 2 has equal momenta at pushoff.

Therefore m1*V1 = m2*V2, and

m1/m2 = V2/V1 = 1/2

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