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December 21, 2014

December 21, 2014

Posted by **Daniel** on Friday, October 14, 2011 at 10:10pm.

y = cosx - sinx (pi, -1)

I found y'= -sinx - cosx

and used the equation of the tangent

y = mx +b

I input the values and get -1 - [(-sinx - cosx) * pi] = b

the answer says it is y = x - 1 - pi

I have no idea how the answer got that.

- calculus -
**bobpursley**, Friday, October 14, 2011 at 10:14pmm= -sinPI-cosPI=1

y= x+b

-1=PI+b

b= -PI-1

y=x-pi-1

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