Friday
May 24, 2013

Homework Help: chemistry

Posted by Colin on Friday, October 14, 2011 at 5:44pm.

A solution of .12 L of 0.160 M KOH is mixed with a solution of .3 L of 0.230 M NiSO4.

the equation for this reaction is:
2KOH (aq)+NiSO4 (aq) ----->K2SO4 (aq)+Ni(OH)2 (s)

.89 grams of Ni(OH)2 precipitate form

I need to know the concentration remaining in the solution of:
1) Ni (II)
2) SO4
3) K


I do not know how to do these nor can i find aid to show me how to do it step by step, so to whoever answers this question, could you also show steps so i can learn how to do this? thank you to whoever puts in their time and helps me!!

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry 101 - A solution of .12 L of 0.160 M KOH is mixed with a solution of ....
Chemistry - A solution of 114 mL of 0.160 molecules KOH is mixed with a solution...
chemistry - A quantity of 12.75 mL of a KOH solution is needed to neutralize 0....
chemistry - A solution of 220mL of 0.200M Koh is mixed with a solution of 120mL...
Chemistry - A solution of 220mL of 0.200M Koh is mixed with a solution of 120mL ...
chemistry - A solution of 0.178 M KOH(28.3 ml) is mixed with 28.9ml of 0.133 M ...
Chemistry--PLEASE HELP - A solution of 220mL of 0.200M Koh is mixed with a ...
chemistry - If it requires 54.7mL of a 0.0765 M HCl solution to complete ...
chemistry - 0.5 L of a 0.30 M HCl solution is titrated with a solution of 0.6 M ...
chem - a.)How many moles of NaOH are required to prepare 2.00L od 0.380M ...

For Further Reading

Search
Members
Community