physics
posted by savannah on .
Two objects with masses of 3.00 kg and 7.00 kg are connected by a light string that passes over a frictionless pulley
(a) Determine the tension in the string.
.N
(b) Determine the magnitude of the acceleration of each mass. .m/s2
(c) Determine the distance each mass will move in the first second of motion if both masses start from rest.
m

A.
m1a1=Tm1g and m2a2=Tm2g are your two equations, substitute and add and you get this >
T= (2xm1xm2)/(m1+m2) all multiplied by 9.8 (g).
T= (2(3.0)(7.0))/(3+7) = 4.2(9.8) = 41.16 N
B.
Then just plug it in to one of your original equations.
m1a1 = Tm1g
(3.0)a = (41.16N)(3.0)(9.8)
a= 3.92 m/s squared.
C. First use equation Vf = Vi + at
Vf = (0) + (3.92)(1)
Vf= 3.92 m/s
Then plug that into V(squared) = Vi(squared) + 2aX
(3.92)squared = 0(squared) + 2 (3.92)X
X= 1.96m