hey drbob222, where did u get 500ml from? question is: 1.00 mL of a 0.0500 M sucrose solution is transferred to a 100 mL volumetric flask, and the flask brought up to volume. 5.00 mL are taken from the 100 mL volumetric flask and transferred to a 0.500 L flask, and it is brought up to volume. What is the resulting concentration of sucrose in the 0.500 L flask?
0.500L = 500 mL
I wanted to keep the units the same in the conversion factor; i.e, I used mL in the numerator so I had to use mL in the denominator. :)
To answer the question, we need to determine the concentration of sucrose in the 0.500 L flask.
Step 1: Calculate the amount of sucrose transferred from the 100 mL volumetric flask to the 0.500 L flask.
1.00 mL of the 0.0500 M sucrose solution is transferred to a 100 mL volumetric flask. This means there is (1.00 mL)(0.0500 mol/L) = 0.0500 mmol of sucrose in the 100 mL flask.
5.00 mL is then taken from the 100 mL flask and transferred to the 0.500 L flask. Therefore, there is (5.00 mL)(0.0500 mmol/100 mL) = 0.00250 mmol of sucrose in the 0.500 L flask.
Step 2: Calculate the concentration of sucrose in the 0.500 L flask.
The resulting concentration of sucrose is given by the equation:
Concentration (M) = moles of solute / volume of solution (in liters)
We have already determined that there are 0.00250 mmol of sucrose in the 0.500 L flask.
To convert mmol to moles, we divide by 1000: 0.00250 mmol / 1000 = 0.00000250 mol.
Now we can calculate the concentration:
Concentration (M) = 0.00000250 mol / 0.500 L = 0.00000500 M
Therefore, the resulting concentration of sucrose in the 0.500 L flask is 0.00000500 M.