Posted by Erin on .
a ball is kicked in the air from the top of a cliff , the path that the ball travels is given by the equation
h(t)=5t^2+17t+22, where h(t) is the height given in meters and t is the time seconds.
a) how high is the cliff ?
b)what is the maximum height the ball reaches ?
c)when will the ball hit the ground
d)write an equation for the axis of symmetry
e)determine the domain and range of the function

Math ( any help would be great!) 
Reiny,
a) would you not be on top of the cliff if t = 0
b) change the equation to vertex form
h(t) = a(th)^2 + k
the value of k will be your maximum height
c) set h(t) = 0 and solve for t as a quadratic
d) once you have the equation in b) the axis of symmetry will be t = h
e) your sketch of the graph will let you determine domain and range.
hint: the t value of the vertex (t,k) is 1.7 
Math ( any help would be great!) 
Erin,
Thankss !!