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April 1, 2015

April 1, 2015

Posted by **Erin** on Thursday, October 13, 2011 at 10:30pm.

h(t)=-5t^2+17t+22, where h(t) is the height given in meters and t is the time seconds.

a) how high is the cliff ?

b)what is the maximum height the ball reaches ?

c)when will the ball hit the ground

d)write an equation for the axis of symmetry

e)determine the domain and range of the function

- Math ( any help would be great!) -
**Reiny**, Thursday, October 13, 2011 at 10:42pma) would you not be on top of the cliff if t = 0

b) change the equation to vertex form

h(t) = a(t-h)^2 + k

the value of k will be your maximum height

c) set h(t) = 0 and solve for t as a quadratic

d) once you have the equation in b) the axis of symmetry will be t = h

e) your sketch of the graph will let you determine domain and range.

hint: the t value of the vertex (t,k) is 1.7

- Math ( any help would be great!) -
**Erin**, Thursday, October 13, 2011 at 11:06pmThankss !!

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